Question

In triangle PQR, Q=72 degrees, R=32 degrees and PR=12. find PQ

Answer 1

6.69 to the nearest hundredth

Explanation:

Use the law of sines

Let x = PQ

`(sin 72)/(12) = (sin 32)/(x)`

x sin 72 = 12 sin 32

`x = (12 sin 32)/(sin 72)`

x = 6.69 to the nearest hundredth