Question

What is the equation of the line that is perpendicular to

the given line and passes through the point (3, 0)?
J(-3,2)
(30)
O 3x + 5y = -9
O 3x + 5y = 9
5x - 3y = -15
O 5x - 3y = 15
54 -3 -2 -1
|(2,71)
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Answer 1

`y + x = 3`

Explanation:

The question is poorly formatted. However, I will take the parameters as follows:

Given

Perpendicular to: J(-3,2) and L(2,7)

Passes through: (3,0)

Required

Write an equation for the line

First, calculate the slope (m) of JL

`m = (y_2 - y_1)/(x_2 - x_1)`

`m = (7-2)/(2+3)`

`m = (5)/(5)`

`m = 1`

Since the line is perpendicula4 to JL, the slope is:

`m_2 = -(1)/(m)`

`m_2 = -(1)/(1)`

`m_2 = -1`

The equation is then calculated using:

`y - y_1 = m(x - x_1)`

`y - 0 = -1(x - 3)`

`y - 0 = -x + 3`

`y = -x + 3`

`y + x = 3`