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16 votes
The sum of two numbers is 100. The different between them is 56. What is the larger number?

User Shaoyihe
by
3.6k points

2 Answers

7 votes

Answer:


here \: given \: that \: sum = 100 \\ diffrence = 56 \\ take \: the \:large \: number = x \\another = y \\ thenx - y = 56 \\ y = x - 56 \\ here \: x + y = 100 \\ x + x - 56 = 100 \\ 2x - 56 = 100 \\ 2x = 156 \\ x = (156)/(2) \\ x = 78 \\ large \: number \: = 78 \\ thank \: you

User Neonstalwart
by
3.4k points
13 votes

Answer:-


\pink{\bigstar} The larger number is
\large\leadsto\boxed{\tt\purple{78}}

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Given:-

  • Sum of two numbers is 100.

  • Difference between the numbers is 56.

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To Find:-

  • The larger number = ?

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Solution:-

Let the two numbers be 'x' and 'y' respectively.

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According to the question:-

Sum of two numbers is 100.


\sf x + y = 100 \dashrightarrow\bold\red{[equation \: 1]}

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Also,

Difference between the numbers is 56.


\sf x - y = 100 \dashrightarrow\bold\red{[equation \: 2]}

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Adding equation [1] and equation [2]:-

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\sf (x + y) + (x - y) = 100 + 56

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\sf x + y + x - y = 156

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\sf 2x = 156

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\sf x = (156)/(2)

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\large{\bold\red{x = 78}}

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Substituting the value of x in equation [1]:-

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\sf x + y = 100

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\sf 78 + y = 100

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\sf y = 100 - 78

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\large{\bold\red{y = 22}}

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Therefore, the numbers are 78 and 22.

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The larger number is 78.

User Nathaniel
by
3.3k points