Question

3.
Where is the weight of an object more on earth, Equator or poles? Why?​

Answer 1

The weight of an object at the poles is more than the weight of the object at the equator

Step-by-step explanation:

The shape of the Earth is an ellipsoid such that the distance from the North and South poles to the Earth's center, R₁, is less than the distance from the Equator to the center of the Earth, R₂

The weight of an object is given by the universal gravitational law as follows;

`Weight = F_(gravity) =G* (M \cdot m)/(R^(2))`

Where;

`F_(gravity)` = The force of gravity = The weight of an object

G = The universal gravitational constant

M = The mass of the Earth

m = The mass of the object

R = The radius of the Earth

Where R₁ < R₂, we have;

The weight at the Poles, W₁ =
`G* (M \cdot m)/(R_1^(2))`

The weight at the Equator, W₂ =
`G* (M \cdot m)/(R_2^(2))`

We have;

`\left(G* (M \cdot m)/(R_1^(2)) \right) > \left(G* (M \cdot m)/(R_2^(2)) \right) \because R_1 < R_2`

Therefore, the weight of an object at the poles, W₁, is more than the weight of the object at the equator, W₂