In 1 mole of manganese(IV) permanganate, there is 1 mole of manganese (Mn).
The molar mass of manganese(IV) permanganate (KMnO4) is 158.034 g/mol.
To find the number of moles of manganese in 1 mole of manganese(IV) permanganate, we use the molar ratio.
From the balanced chemical equation:
4 MnO4 + 2 H2O = 4 MnO2 + 3 O2 + 4 OH-
We see that 4 moles of MnO4 react to form 4 moles of MnO2.
Therefore, in 1 mole of MnO4 there are 1 mole of manganese (Mn).
So, in 1 mole of manganese(IV) permanganate, there is 1 mole of Mn.