Question

Arrange these compounds by their expected boiling point. Highest boiling point Lowest boiling point CH3OH, CH3CI CH4.

Answer 1

The order of compounds from highest to lowest boiling point is methanol (CH3OH), methyl chloride (CH3Cl), and methane (CH4) due to differences in their polarity and ability to form hydrogen bonds.

Step-by-step explanation:

The student has asked to arrange the compounds CH3OH, CH3Cl, and CH4 by their expected boiling points, from highest to lowest. To determine this order, we must compare the molar masses and the polarities of the compounds, as these characteristics influence boiling points.

Methanol (CH3OH) is both polar and capable of hydrogen bonding, which significantly increases its boiling point. Next is methyl chloride (CH3Cl), which is polar but does not have hydrogen bonds. It still has a higher boiling point than methane (CH4) because methane is a nonpolar molecule and thus only has weak London dispersion forces.

The correct order from highest to lowest boiling point is therefore: CH3OH > CH3Cl > CH4.

Answer 2

Answer: The given compounds are arranged according to decreasing boiling point as
`CH_(3)OH > CH_(3)Cl > CH_(4)`.

Step-by-step explanation:

The temperature at which vapor pressure of a substance becomes equal to the atmospheric pressure is called boiling point.

Stronger is the intermolecular forces present the atoms of a molecule more heat will be required by it to break the bond between its atoms. Hence, more will the boiling point of the molecule.

In
`CH_(3)OH` (methanol), there is hydrogen bonding present which is a stronger force. So, it will have highest boiling point as compared to
`CH_(3)Cl` and
`CH_(4)`.

In
`CH_(3)Cl` (chloroform), there is more electronegative atom attached (Cl) is attached to less electronegative atom (C and H). So, electrons are more pulled towards the chlorine atom. So, boiling point of
`CH_(3)Cl` is more than methane
`(CH_(4))`.

Thus, we can conclude that given compounds are arranged according to decreasing boiling point as
`CH_(3)OH > CH_(3)Cl > CH_(4)`.