Question

A 2.714 gram sample of a hydrate of sodium carbonate is placed in a test

tube and heated until the mass is constant. If the mass of the dry sodium
carbonate is 1.006 grams. What was the mass of water driven off and what
was the percentage of water in the hydrate?

Answer 1

`m_(water)=1.708g`

Step-by-step explanation:

Hello!

In this case, since the total mass of the sample is 2.714 g and the mass of the anhydrous salt is 1.006 g; we infer the mass of water is:

`m_(water)=2.714g-1.006g\\\\m_(water)=1.708g`

Moreover, the percentage of water in the hydrate is calculated by dividing the mass of water by the mass of the total hydrate:

`\% water=(1.708g)/(2.714g)*100\% \\\\\% water=62.9\%`

Best regards!