Question

PLEASE HELP ME :(
(X+4)^2-3(x+4)-3=0
Select the solutions of the og equation

Answer 1

`\boxed{\textsf{ The value of x is }\bf{ (-5\pm√(21))/(2)}.}`

Explanation:

A quadratic equation is given to us and we need to find the Solutions of the quadratic equation . So the given equⁿ is ,

`\sf\implies (x+4)^2 -3(x+4) -3 = 0`

Firstly let's simpify the quadratic equation and then use the quadratic formula also known as " Shreedhacharya's Formula" .

Taking the given equation :-

`\sf\implies (x+4)^2 -3(x+4) -3 = 0\\\\\sf\implies x^2 + 16 + 8x -3x -12 -3 = 0 \\\\\sf\implies x^2+5x +1 = 0`

Now let's use the Quadratic formula ,

Quadratic Formula :-

`\qquad\boxed{\boxed{ \sf x =( -b \pm √( b^2-4ac))/(2a) }}`

With respect to Standard form ax² + bx + c form. Here a = 1 , b = 5 and c = 1 .

`\sf\implies x = ( -5\pm √( (5)^2-4(1)(1)))/(2(1)) \\\\\sf\implies x = ( -5 \pm √( 25 -4 ) )/(2) \\\\\sf\implies \boxed{\pink{\sf x = (-5+√(21))/(2), (-5-√(21))/(2) }}`