Midsegments geometry acellus pls helppfpfpff

Lamonte asked Nov 11, 2022

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10 votes

Lamonte asked Nov 11, 2022

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11 votes

Answer:

BC = 28

Explanation:

The midsegment DF is half the measure of the third side BC , then

BC = 2 × DF = 2 × 14 = 28

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