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Assume that I = E/(R + r), prove that 1/1 = R/E + r/E​
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28 votes
Assume that I = E/(R + r), prove that 1/1 = R/E + r/E​

User MetaChrome
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12 votes


\implies {\blue {\boxed {\boxed {\purple {\sf { (1)/(I) = (R)/(E) + (r)/(E) }}}}}}


\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}


I = ( E)/( R + r) \\


➺\:(I)/(1) = (E)/(R + r) \\

Since
(a)/(b) = (c)/(d) can be written as
ad = bc, we have


➺ \: I \: (R + r) = E * 1


➺ \: (1)/(I) = (R + r)/(E) \\


➺ \: (1)/(I) = (R)/(E) + (r)/(E) \\


\boxed{ Hence\:proved. }


\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

User Nicholas Tower
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