Question

Assume that I = E/(R + r), prove that 1/1 = R/E + r/E​

Answer 1

`\implies {\blue {\boxed {\boxed {\purple {\sf { (1)/(I) = (R)/(E) + (r)/(E) }}}}}}`

`\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}`

`I = ( E)/( R + r) \\`

`➺\:(I)/(1) = (E)/(R + r) \\`

Since
`(a)/(b) = (c)/(d)` can be written as
`ad = bc`, we have

`➺ \: I \: (R + r) = E * 1`

`➺ \: (1)/(I) = (R + r)/(E) \\`

`➺ \: (1)/(I) = (R)/(E) + (r)/(E) \\`

`\boxed{ Hence\:proved. }`

`\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}`