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8x-5y=-118x−5y=−118, x, minus, 5, y, equals, minus, 11 xxx-intercept: \Big((left parenthesis ,,comma \Big))right parenthesis yyy-intercept: \Big((left parenthesis

User MTuran
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1 Answer

9 votes

Given:

The equation is


8x-5y=-11

To find:

The x-intercept and y-intercept of the given equation.

Solution:

We have,


8x-5y=-11

For x-intercept, y=0.


8x-5(0)=-11


8x=-11


x=-(11)/(8)


x=-1.375

So, the x-intercept is at point (-1.375,0).

For y-intercept, x=0.


8(0)-5y=-11


-5y=-11


y=(-11)/(-5)


y=2.2

So, the y-intercept is at point (0,2.2).

User Whmkr
by
7.5k points
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