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Un proton penetra perpendiculares en un campo magnetico de 5 teslas con una velocidad de 2.10 m/s calcula

User Mgv
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1 Answer

8 votes
8 votes

Answer:

The magnetic force acting on the proton is 1.68 x 10^-18 N.

Step-by-step explanation:

magnetic field, B = 5 T

speed , v = 2.1 m/s

charge q = 1.6 x 10^-19 C

Angle, A = 90 degree

The magnetic force on the charge particle is given by


F = q v B sin A\\\\F = 1.6* 10^(-19)* 2.1* 5* sin 90\\\\F = 1.68* 10^(-18) N

User Yamahari
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