Answer:
781×10¯² g of MgCl₂.
Step-by-step explanation:
The balanced equation for the reaction is given below:
Mg + 2HCl —> MgCl₂ + H₂
Next, we shall determine the mass of HCl that reacted and the mass of MgCl₂ produced from the balanced equation. This is illustrated below:
Molar mass of HCl = 1 + 35.5
= 36.5 g/mol
Mass of HCl from the balanced equation = 2 × 36.5 = 73 g
Molar mass of MgCl₂ = 24 + (35.5×2)
= 24 + 71
= 95 g/mol
Mass of MgCl₂ from the balanced equation = 1 × 95 = 95 g
SUMMARY:
From the balanced equation above,
73 g of HCl reacted to produce 95 g of MgCl₂.
Finally, we shall determine the mass of MgCl₂ produced by the reaction of 6 g of HCl. This can be obtained as follow:
From the balanced equation above,
73 g of HCl reacted to produce 95 g of MgCl₂.
Therefore, 6 g of HCl will react to produce = (6 × 95)/73 = 781×10¯² g of MgCl₂.
Thus, 781×10¯² g of MgCl₂ were obtained from the reaction.