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A spring has a spring constant of 25 Newtons per meter. The minimum force required to stretch the spring 0.20 meter from its equilibrium position is approximately
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22 votes
A spring has a spring constant of 25 Newtons per meter. The minimum force required to

stretch the spring 0.20 meter from its equilibrium position is approximately

User Whatoncewaslost
by
6.3k points

2 Answers

3 votes

Answer:

6.3 N

Step-by-step explanation:

F=kx

F=(25N/m)(0.25m)

6.3 N

User Brightshine
by
6.1k points
5 votes

Answer:

6.3N

Step-by-step explanation:

Guessed it right on castle learning

User Vvanpelt
by
6.8k points
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