At what frequency would an inductor of inductance 0.8H have a reactance of 12000^?

Rob Farley asked Sep 19, 2022

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Rob Farley asked Sep 19, 2022

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19 votes

Step-by-step explanation:

The inductive reactance
X_L is given by

$X_L = \omega L = 2 \pi fL$

Solving for f, we get

$f = (X_L)/(2 \pi L) = \frac{12000\:\text{ ohms}}{2\pi (0.8\:H)}$

$\:\:\:\:\:\:\:= 2387.3\:\text{Hz}$

Lowkey answered Sep 23, 2022

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