Question

which equation models the same quadratic relationship as function f? f(x)=x^2+12x+4 a) y=(x-6)^2+40 b) y=(x+6)^2-32 c) y=(x-6)^2-32 d) y=(x+6)^2+40​

Answer 1

B. Y=(x+6)²-32

Explanation:

hope it helps

Answer 2

9514 1404 393

Answer:

b) y=(x+6)^2-32

Explanation:

Add and subtract the square of half the x-coefficient to put into vertex form.

f(x) = x^2 +12x +4 . . . . . given

y = x^2 +12x +36 +4 -36 . . . . add and subtract (12/2)^2 = 36

y = (x +6)^2 -32 . . . . . . . . . . . write in vertex form