Question

`-x^(2) +7x-10=o\\`
solve using sum product method

Answer 1

`▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪`

Let's solve ~

`\qquad \sf  \dashrightarrow \: - {x}^(2) + 7x - 10 = 0`

`\qquad \sf  \dashrightarrow \: - {x}^(2) + 2x + 5x - 10 = 0`

`\qquad \sf  \dashrightarrow \: - x(x - 2) + 5(x - 2) = 0`

`\qquad \sf  \dashrightarrow \: ( x- 2)( - x + 5) = 0`

Therefore, there are two solutions for x ;

Case 1

`\qquad \sf  \dashrightarrow \: x - 2 = 0`

`\qquad \sf  \dashrightarrow \: x = 2`

Case 2

`\qquad \sf  \dashrightarrow \: - x + 5 = 0`

`\qquad \sf  \dashrightarrow \: - x = - 5`

`\qquad \sf  \dashrightarrow \: x = 5`