Answer:
6 g of O₂
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2ZnS + 3O₂ —> 2ZnO + 2SO₂
From the balanced equation above,
2 moles of ZnS reacted with 3 moles of O₂.
Next, we shall determine the number of mole of O₂ required to react with 0.125 mole of ZnS. This can be obtained as follow:
From the balanced equation above,
2 moles of ZnS reacted with 3 moles of O₂.
Therefore, 0.125 mole of ZnS will react with = (0.125 × 3)/2 = 0.1875 mole of O₂.
Thus, 0.1875 mole of O₂ is needed for the reaction.
Finally, we shall determine the mass of 0.1875 mole of O₂. This can be obtained as follow:
Mole of O₂ = 0.1875 mole
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ =?
Mass = mole × molar mass
Mass of O₂ = 0.1875 × 32
Mass of O₂ = 6 g
Therefore, 6 g of O₂ is required for the reaction.