51.0k views
22 votes
Five double-digit numbers We have five consecutive positive double-digit integers. If we swap places on the numbers in the largest number, the sum of the five numbers increases by 1 more than the mean of the original numbers. What is the lowest number?

User Brivvirs
by
7.1k points

1 Answer

5 votes

Answer:

  • 33

Explanation:

Let the numbers are:

  • x, x + 1, x + 2, x + 3 and x + 4
  • Their sum is 5x + 10
  • Their mean is (5x + 10)/2 = x + 2

If we swap the digits on the largest number, the sum increases by 1 more than x + 2

We are looking for the number x + 4 = ab such that:

  • ba - ab = ab - 2 + 1
  • ba = 2ab - 1
  • 10b + a = 2(10a + b) - 1
  • 10b + a = 20a + 2b - 1
  • 8b = 19a - 1
  • 19a = 8b + 1

By trial method we get the solution:

  • a = 3, b = 7

Since x + 4 = 37, the lowest number is:

  • x = 37 - 4 = 33

Lets verify:

  • 33, 34, 35, 36, 37

The sum is:

  • 5*33 + 10 = 175

The mean is:

  • 35

Change the largest number tp 73 and find the sum again:

  • 175 + (73 - 37) = 175 + 36 = 175 + 35 + 1

The sum has increased by 1 more than 35

User Lawrence DeSouza
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories