Question

A bottling company marks a 0 for every bottle that comes out correct and a 1 for every defective bottle. Estimate the probability that the next bottle is defective

Answer 1

1/20

Explanation:

000000000000100000

It is asking the probability of a defective bottle

there is one defective bottle out of 20

Answer 2

See Explanation

Explanation:

Given

`0 \to` Correct

`1 \to` Defective

Required

The probability that the next is defective

The question is incomplete because the list of bottles that came out is not given.

However, the formula to use is:

`Pr = Num ber\ o f\ d e f e c t i v e / T o t a l\ b o t t l e s`

Take for instance, the following outcomes:

`0\ 1\ 0\ 0\ 0\ 1\ 0\ 0\ 1\ 1\ 0\ 0\ 0\ 1`

We have:

`Total = 14`

`D e f e ctive = 9` --- i.e. the number of 0's

So, the probability is:

`Pr = 9 / 14`

`Pr = 0.643`