43.0k views
17 votes
Help with both questions please <3

Help with both questions please <3-example-1
User Srinivas B
by
8.0k points

1 Answer

6 votes

Answer:

Explanation:

Part A

A square pyramid surface area can be calculated using A = Lw (which gives you surface area of the base square) & 4 of A = bh/2 (which gives you surface area of the 4 triangles on the side)

This means overall A = Lw + 4(bh/2)

Length = L = 4"

Width = w = 4"

Base = b = w = L = 4"

Height = h = 6"

A = Lw + 4(bh/2)

A = Lw + 2bh This is the answer after simplifying

A = (4")(4") + 2(4")(6") This is the numerical expression.

A = 16" + 48" = 64" This is the numerical answer.

A square prism surface area can be found using 2 of A = Lw (which represents the surface area of the 2 squares) and 4 of A = Lh (which gives you the surface area of the 4 rectangles).

This means overall A = 2Lw + 4Lh

Length = L = 4"

Width = w = 4"

Height = h = 6"

A = 2Lw + 4Lh

A = 2(4")(4") + 4(4")(6") This is the numerical expression.

A = 128" This is the numerical answer.

Part B

To see the difference between the 2 polyhedrons, I will place them as follows.

Pyramid Area = A = (4")(4") + 2(4")(6")

Prism Area = A = 2(4")(4") + 4(4")(6")

The numerical expression shows that the surface area of the prism has one more square area (as represented by 4"x4"), and has 2 more rectangular area (as represented by 4"x6").

The difference of the 2 numerical expressions can be found using subtraction:

A = [2(4")(4") + 4(4")(6")] - [(4")(4") + 2(4")(6")]

A = (4")(4") + 2(4")(6")

Hope this helps.

User Kiefer
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories