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If 12.3 g of Cu is deposited at the cathode of an electrolytic cell after 5.50 h, what was the current used?​

User RerwinX
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1 Answer

8 votes
8 votes

Answer:

Current used = 1.90 A

Step-by-step explanation:

The Faraday's first law of electrolysis states:

M = ZIt

where: M is the mass of the element deposited, Z is the electrochemical equivalence of the element, I is the amount of current required and t is the time taken.

From the given question, M = 12.3 g, t = 5.5 h (19800 s) and Z = 0.0003296 g/C.

So that,

12.3 = 0.0003296 x I x 19800

12.3 = 6.52608 I

I =
(12.3)/(6.52608)

= 1.88475

I = 1.90 A

The value of the current used used is 1.90 A

User Artsin
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