Question

A tin contained 10 3/5 liter of oil . 1 2/7 liter of oil was leaked and 7 1/10 liter used up .Find how much oil is left in the tin.​

Answer 1

2.2 l of oil was left.

Explanation:

`Total=10(3)/(5) =10.6l\\Used=7(1)/(10) =7.1l\\Leaked=1(2)/(7) =1.28l\\`

Total used=7.1l+1.28l=8.38l

`Left=10.6l-8.38l=2.22l`

Answer 2

The liter of oil tin contained

`= 10 \ (3)/(5)`

The liter of oil used and leak

`= 1 (2)/(7) + 7 \ (1)/(10)`

`= (9)/(7) + (71)/(10)`

`= (9 * 10)/(7 * 10) + (71 * 7)/(10 * 7)`

`= (90)/(70) + (497)/(70)`

`= (587)/(70)`

The liter of oil left in the tin

`= (53)/(5) - (587)/(70)`

`= (53 * 14)/(5 * 14) - (587 * 1)/(70 * 1)`

`= (742 - 587)/(70)`

`= (155 / 5)/(70 / 5)`

`= (31)/(14)`

`= 2 (3)/(14)`

~nightmare 5474~