Question

g to generate electricity, solar panels typically absorb visible light. How many photons of light with a frequency of 5045x10 14 hz does a solar panel absorb to create 360 kj

Answer 1

the number of photons absorbed by the solar panel is 1.08 x 10²¹

Step-by-step explanation:

Given;

frequency of each photon absorbed, f = 5045 x 10¹⁴ Hz

energy to be created by the solar panel, E = 360 kJ = 360,000 J

The energy of each photon absorbed is calculated as;

`E_(photon) = hf\\\\where;\\\\h \ is \ Planck's \ constant = 6.626 * 10^(-34) \ Js\\\\E_(photon) = (6.626 * 10^(-34) )(5045 * 10^(14))\\\\E_(photon) = 3.343 * 10^(-16) \ J`

let the number of photons absorbed = n

`n(E_(photon)) = 360,000 \ J\\\\n = (360,000 \ J)/(3.343 * 10^(-16) \ J) \\\\n = 1.08 * 10^(21) \ photons`

Therefore, the number of photons absorbed by the solar panel is 1.08 x 10²¹