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In the reaction :N2 + 3H2----2NH3 how many grams of H2 are needed to produce 1 mole on ammonia

2 Answers

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Final answer:

To produce 1 mole of ammonia, you would need 3.03 grams of H2.

Step-by-step explanation:

In the reaction N2 + 3H2 → 2NH3, we can see that the ratio between H2 and NH3 is 3:2. This means that for every 3 moles of H2, 2 moles of NH3 are produced. Since we are given 1 mole of NH3, we can set up a proportion to find the amount of H2 needed:

1 mole NH3 = x moles H2 / 3 moles H2

Solving for x, we find that x = 1.5 moles of H2. Now, we can convert moles of H2 to grams using the molar mass of H2:

1.5 moles H2 * 2.02 g/mol = 3.03 grams of H2

User Christopher Milne
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Start with moles of ammonia you want to produce, then convert to how many moles of H2 you need to get one mole of ammonia, then convert that to grams :)
In the reaction :N2 + 3H2----2NH3 how many grams of H2 are needed to produce 1 mole-example-1
User Flavio CF Oliveira
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