Question

I have no idea how to do this, so if someone could at least do one of these I’ll be grateful <3

Answer 1

9. -35+7n

10. 16m+8

11. 6xy-6xz

Explanation:

You multiplying the terms inside the ( ) by the outside factor.

This is call distributive property, a(b+c)=ab+ac.

Also, a(b+c)=(b+c)a by commutative property.

It also works over the operation subtraction since subtraction is just a disguised addition (addition of the opposite). That is, a(b-c)=ab-ac.

Anyhow, let's look at 9.,10., and 11..

9.

-7(5-n)

(-7)(5-n)

(-7)(5)-(-7)(n)

-35+7n

10.

8(2m+1)

(8)(2m)+(8)(1)

16m+8

11.

6x(y-z)

(6x)(y-z)

(6x)(y)-(6x)(z)

6xy-6xz

Hint on 7. It's like all the other problems. That is, it is equivalent to doing 8(2+g).

If you want comment below, if you want me to check any of yours or if you have any questions.

Answer 2

Answers are below!

Explanation:

(2 + g) (8)

= (2 + g) (8)

Add a 8 after the 2, and flip.

= (2)(8) + (g)(8)

= 16 + 8g

= 8g + 16

= (4) (8 + -5g)

Add another 4, then flip.

= (4) (8) + (4) (-5g)

= 32 − 20g

= - 20g + 32

−7 (5-n)

= (−7) (5 + -n)

Add another 7, then flip.

= (−7) (5) + (-7) (-n)

= −35 + 7n

= 7n - 35

Use the distributive property.

a (b + c) = ab + ac

a = 8

b = 2m

c = 1

= 8 × 2m + 8 × 1

Simplify, you get 16m + 8.

Use the distributive property.

a (b + c) = ab + ac

a = 6x

b = y

c = z

= 6xy - 6xz is the answer.

`\mathrm{Apply\:the\:distributive\:law}:\quad \\\:a\left(b+c\right)=ab+ac`

`a=-3,\:b=2b,\:c=2a`

`=-3\cdot \:2b+\left(-3\right)\cdot \:2a`

Apply minus plus rules.

`=-3\cdot \:2b+\left(-3\right)\cdot \:2a`

Multiply the numbers.

3 x 2 = 6