Answer:
33.33 repeating percent.
Explanation:
So using the 20 percent, we can guess there will be 2 bulbs that are defective in the sample. So 2/10. But we are guessing there will be 6;6/10. We alreadly know the proablity of that is low. To be exact 2/6 (as they are both over ten we can get rid of that) or 1/3, or 33.333 repeating percent.
Hope this helps!