If f(x) = 4x ^ 2 - 4x - 8 and g(x) = 2x ^ 2 + 3x - 6 then f(x) - g(x) * i * s

DaRoGa asked Apr 16, 2022

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DaRoGa asked Apr 16, 2022

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13 votes

Answer:

$4 {x}^(2) - 4x - 8 - (2 {x}^(2) + 3x - 6) = 4 {x}^(2) - 4x - 8 - 2 {x}^(2) - 3x + 6 = 2 {x}^(2) - 7x - 2$

Kentaro answered Apr 21, 2022

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