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10 votes
10 votes
Please help me, It's my last question :)

Imagine you have a 5L balloon that you would like to fit into a 3L container. The current temperature is 298 K. At what temperature would you need to change the system to allow the balloon to fit into the container? Show your work.

User DonDyck
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2.7k points

1 Answer

25 votes
25 votes

Given:


V_(1) = \text{5 L}


T_(1) = \text{298 K}


V_(2) = \text{3 L}

Unknown:


T_(2)

Solution:


(V_(1))/(T_(1)) = (V_(2))/(T_(2))


T_(2) = T_(1) * (V_(2))/(V_(1))


T_(2) = \text{298 K} * \frac{\text{3 L}}{\text{5 L}}


\boxed{T_(2) = \text{179 K}}


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User The Puma
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