Question

A 50.0 g sample of liquid water at 56.0°C, heats to 91.0 "C. How much energy is

involved in this change? (Heat capacity of liquid water is 4.17 J/gºC) (Q
=mcAT)
A. 7298 J B. 12038 J
C. 204480 J D. 17807 J

Answer 1

A

Step-by-step explanation:

using

mC∆t

50×4.17×(91-56)

=50×4.17×35

=7297.5

~ 7298 J