Question

I need help ASAP;
Algebra 1: I think it's about exponential growth.

Answer 1

Explanation:

The given equation assumes a 12 cubic inch initial volume. The question wants to know when, in minutes, the volume, y, reaches 36 in^3:

y = 12*(2)^(t/60), where t is time in minutes

Therefore:

36 = 12*(2)^(t/60)

3 = (2)^(t/60)

log(3) =(60/t) log(2)

t = 60log(3)/log(2)

t = 95.1 minutes