Question

A cannonball is fired perfectly horizontally from the top of a 210 m tall cliff. It is fired with an initial velocity of 50 m/s. What is the horizontal distance covered by the cannonball before it hits the ground?

Answer 1

the horizontal distance covered by the cannonball before it hits the ground is 327.5 m

Step-by-step explanation:

Given;

height of the cliff, h = 210 m

initial horizontal velocity of the cannonball, Ux = 50 m/s

initial vertical velocity of the cannonball, Uy = 0

The time for the cannonball to reach the ground is calculated as;

`h = u_yt - (1)/(2) gt^2\\\\h = 0 - (1)/(2) gt^2\\\\t = \sqrt{(2h)/(g) } \\\\t = \sqrt{(2* 210)/(9.8) }\\\\t = 6.55 \ s`

The horizontal distance covered by the cannonball before it hits the ground is calculated as;

`X = U_x * \ t\\\\X = 50 * \ 6.55\\\\X = 327.5 \ m`

Therefore, the horizontal distance covered by the cannonball before it hits the ground is 327.5 m