Question

What is an equation of the line that passes through the point (-5 7) and is parallel to the line x-5y=15

Answer 1

Explanation:

Parallel lines have same slope.

y = mx + b

Slope = m & y-intercept = b

x - 5y = 15

-5y = -x + 15

y =
`(-1)/(-5)x + (15)/(-5)\\\\`

`y = (1)/(5)x - 3`

so, slope = 1/5 ; (-5 , 7)

y -y1 = m(x -x1)

`y - 7 = (1)/(5)(x- [-5])\\\\y - 7 =(1)/(5)(x + 5)\\\\y - 7 = (1)/(5)x+5*(1)/(5)\\\\y - 7 =(1)/(5)x+1\\\\y =(1)/(5)x+1+7\\\\y=(1)/(5)x + 8`