Question

Find the product. Multiplication of the binomial.

Answer 1

We have,
`(2r+3)(3r^2+4r+5)` or more generally,

`(a+b)(c+d+e)=ac+ad+ae+bc+bd+be`

So using that, we find,

`(2r+3)(3r^2+4r+5)=6r^3+8r^2+10r+9r^2+12r+15`, then collect terms with same exponent and get
`\boxed{6r^3+17r^2+22r+15}`.