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36 votes
36 votes
A 0.495-kg hockey puck, moving east with a speed of 4.50 m/s , has a head-on collision with a 0.720-kg puck initially at rest. Assuming a perfectly elastic collision, what will be the speed (magnitude of the velocity) of each object after the collision?

User MangduYogii
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1 Answer

14 votes
14 votes

Answer:

a)
v_1=-0.833m/s

b)
V_2=12.5m/s

Step-by-step explanation:

From the question we are told that:

Hockey puck Mass
m_1=0.495kg

Hockey puck Speed
u_1=4.50m/s

Puck Mass
m_2=0.720kg

Assuming

Initial speed of Puck
u_2=0

Generally the equation for Speed of First Puck is mathematically given by


v_1=((m_1-m_2)/(m_1+m_2))*v_1+((2m_2)/(m_1+m_2))u_2


v_1=((0.495-0.720)/(0.495+0.720))*4.50+0


v_1=-0.833m/s

Generally the equation for Speed of Second Puck is mathematically given by


V_2=((2m_1)/(m_1+m_2))u_2-((m_1-m_2)/(m_1+m_2))v


V_2=((2*0.495)/(0.495*0.720))*4.50-0


V_2=12.5m/s

User Marmstrong
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3.1k points