Answer:
![(11)/(36)](https://img.qammunity.org/2022/formulas/mathematics/college/qndhs7cy6rmsli119cxms9lwmlt56xe1vm.png)
Explanation:
Total outcomes for rolling a pair of six-sided dice n(S)= 6 x 6 =36
Let A be the event that the first die is one and B be the event that the sum of the dice is eight.
A = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)}
P(A)=
![=(n(A))/(n(S))=(6)/(36)](https://img.qammunity.org/2022/formulas/mathematics/college/y9uky85sqxwe79ag91urjk0hjes3zos498.png)
B= {(2,6), (6,2), (3,5), (5, 3), (4,4)}
P(B)=
![=(n(B))/(n(S))=(5)/(36)](https://img.qammunity.org/2022/formulas/mathematics/college/rtq4ble2flmvi7s7x7uolvb4awofngxq2m.png)
A ∩ B = Ф
P(A ∩ B)=0
P(A or B)= P(A)+P(B)+P(A∩ B)
![=(6)/(36)+(5)/(36)+0\\=(11)/(36)](https://img.qammunity.org/2022/formulas/mathematics/college/vfimp4y08boxdmh585tx4568gfelf1jw4n.png)
Hence, P(A or B) =
![(11)/(36)](https://img.qammunity.org/2022/formulas/mathematics/college/qndhs7cy6rmsli119cxms9lwmlt56xe1vm.png)