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36 votes
36 votes
Answer pleaseeeeeee !!!!

Answer pleaseeeeeee !!!!-example-1
User Lukas Kolletzki
by
2.5k points

1 Answer

20 votes
20 votes

Answer:

Option C.

Explanation:

Ok, first we know that:

Tan(0) = 0

While in the graph, we can see that:

f(0) = -2

Then our function will be something like:

f(x) = tan( k*x) - 2

We also can see that the graph has asymptotes at x = π/2 and at x = -π/2

While the normal tangent equation has the asymptotes at x = pi

So here we have that:

k*(pi/2) = pi

k = pi*(2/pi) = 2

k = 2

then the function is something like:

f(x) = tan(2*x) - 2

If we look at the options, we can see one that is:

tan( 2*(x + π)) - 2

we can rewrite this as:

tan(2*x + 2π) - 2

And remember that the period of a trigonometric function is 2π

This means that:

tan(a + 2π) = tan(a)

Then:

tan(2*x + 2π) - 2 = tan(2*x) - 2

Which is the function that we found.

Then the correct option is C

User Jeffrey Chen
by
2.5k points
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