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Hydrogen selenide (H₂Se) reacts with water according to the following equation H₂Se + H₂O → SеH¯ + H₂O* In three to five sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction (4 points)​

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In the given reaction, hydrogen selenide (H₂Se) acts as the acid, while water (H₂O) acts as the base. The conjugate acid is SeH¯, and the conjugate base is H₂O*.

Hydrogen selenide (H₂Se) acts as the acid because it donates a proton (H⁺) to water. Water (H₂O) acts as the base because it accepts the proton from hydrogen selenide.

The tendency for a substance to act as an acid or base can be explained using patterns in the periodic table. In this case, hydrogen selenide (H₂Se) is an acid because it contains hydrogen (H) bonded to a more electronegative element, selenium (Se). Water (H₂O) acts as a base because oxygen (O) is more electronegative than hydrogen (H), making it more likely to accept a proton.
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