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what is the magnitude of the magnetic field of a long straight wire carrying 100 a as measured a distance 10 meters away?

User Cerebrate
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1 Answer

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The magnetic field at a distance r from a straight wire is given by:


B=(\mu_0I)/(2\pi r)

where
\mu_0=4\pi*10^(-7) \frac{\text{H}}{\text{m}} is the magnetic constant

So, plugging everything in:


B=(\mu_0I)/(2\pi r)=B=((4\pi*10^(-7))(100))/((2\pi)(10))=2*10^(-6)\text{T}

User TKH
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