Question

Using the equation in the picture - calculate the

following: A rifle has a barrel 80 cm long. The bullet
leaves the barrel at a velocity of 800 m/s. Calculate
the acceleration of the bullet as it leaves the barrel.
(be aware of units!!)
V*2-U*2=2xaxX

Answer 1

400,000 m/s²

Step-by-step explanation:

Given:

x = 80 cm = 0.80 m

u = 0 m/s

v = 800 m/s

Find: a

v² − u² = 2ax

(800 m/s)² − (0 m/s)² = 2a (0.80 m)

a = 400,000 m/s²