Final answer:
The cross between a purebred black mouse and a purebred white mouse suggests incomplete dominance, with the F1 generation being all black (BW genotype) and the F2 generation showing a phenotypic ratio corresponding to a complex inheritance pattern. To determine the probability of black offspring from an F2 white and black mouse cross, information on the genotypic ratio of the black mice is needed.
Step-by-step explanation:
To answer the question about the cross between a purebred black mouse and a purebred white mouse that yields all black F1 offspring, and the F2 generation phenotypic ratio of White: 22, Black: 175, Gray: 114, we need to consider a form of incomplete dominance, since we observe a third gray phenotype.
For the F1 generation, all offspring are black, which suggests that black (B) is dominant over white (W) and gray is a result of heterozygosity (BW). The parental generation (P) would therefore have genotypes BB (black) and WW (white). The F1 generation, which is all black, would have the genotype BW.
For the F2 generation, crossing two BW genotyped mice, we would expect the following phenotypic ratio: 1 BB (black): 2 BW (gray): 1 WW (white). However, the observed phenotypic ratio is roughly 9 (black): 6 (gray): 3 (white), suggesting that a 9:3:4 ratio occurs due to a more complex inheritance pattern.
When crossing the F2 white (WW) mice with the F2 black mice (which could be BB or BW), we cannot determine the probability of black offspring without knowing the genotypic ratio of the black mice. Assuming all black mice are BB, all offspring would be black. If the black mice are a mix of BB and BW, then the probability of a black offspring will depend on the presence of the B allele from the black parent.
Since this calculation relies on the precise genotypic makeup of the F2 black mice, which we do not have, we cannot calculate the exact probability without further information.