Question

An arrow traveling 800. m/s horizontally hits a target 180. m away. How far does the bullet fall before it hits the target?

Answer 1

0.248 m

Step-by-step explanation:

First find the time it takes for the arrow to reach the target. In the x direction:

s = 180. m

u = 800. m/s

a = 0 m/s

Find: t

s = ut + ½ at²

180. = (800.) t + ½ (0) t²

t = 0.225 s

Next, find the distance the arrow falls in that time. In the y direction:

u = 0 m/s

a = -9.8 m/s²

t = 0.225 s

Find: s

s = ut + ½ at²

s = (0) (0.225) + ½ (-9.8) (0.225)²

s = -0.248 m

The arrow falls 0.248 meters.