Question

a gas has a pressure of 78 atm, a volume of 42l, and a temperature of 750k. what will the volume (in liters) be when the temperature increases to 910k and the pressure increases to 125atm?

Answer 1

To find the new volume of a gas when both temperature and pressure change, the combined gas law is used. The initial conditions are given and the final conditions are applied to the formula V2 = (P1 * V1 * T2) / (T1 * P2) to calculate the new volume.

Step-by-step explanation:

The question involves finding the new volume of a gas when both the temperature and pressure change, which is a direct application of the combined gas law. The combined gas law is expressed as (P1 * V1) / T1 = (P2 * V2) / T2, where P is pressure, V is volume, and T is temperature. For this problem, the initial conditions are a pressure of 78 atm, a volume of 42 L, and a temperature of 750 K. The final conditions are a temperature of 910 K and a pressure of 125 atm.

To find the new volume (V2), we rearrange the equation to V2 = (P1 * V1 * T2) / (T1 * P2). Substituting the given values, we get V2 = (78 atm * 42 L * 910 K) / (750 K * 125 atm). After performing the calculation, we find the new volume of the gas.

It's important to note that when performing these calculations, temperature must be in Kelvins to satisfy the requirements of the combined gas law. Answering this question demonstrates understanding of how changes in temperature and pressure affect the volume of a gas.

Answer 2

The final volume of a gas with initial conditions of 78 atm pressure, 42 L volume, and 750 K temperature changing to 910 K temperature and 125 atm pressure is calculated using the combined gas law to be 24.08 liters.

Step-by-step explanation:

The question involves calculating the volume of a gas when its temperature and pressure change. To find the new volume, we can use the combined gas law, which states that for a fixed amount of gas, (P1 * V1) / T1 = (P2 * V2) / T2, where P is pressure, V is volume, and T is the temperature in Kelvin. We have the initial values: P1 = 78 atm, V1 = 42 L, T1 = 750 K, and the final values are P2 = 125 atm and T2 = 910 K.

Plugging these values into the combined gas law we get:

(78 atm * 42 L) / 750 K = (125 atm * V2) / 910 K

By cross-multiplying and solving for V2, the new volume, we find:

V2 = (78 atm * 42 L * 910 K) / (750 K * 125 atm)

V2 = 24.08 L

Therefore, the final volume of the gas when the temperature increases to 910 K and the pressure increases to 125 atm is 24.08 liters.