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Answer:
20 J
Step-by-step explanation:
Elastic potential energy of a spring is:
EE = ½ kx²,
where k is the spring constant and x is the displacement.
Given k = 95 N/m and x = 0.65 m:
EE = ½ (95 N/m) (0.65 m)²
EE = 20. J
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