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What is the potential energy of a spring that is compressed 0.65 m by a 25 kg block if the spring constant is 95 N/m?

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Answer:

20 J

Step-by-step explanation:

Elastic potential energy of a spring is:

EE = ½ kx²,

where k is the spring constant and x is the displacement.

Given k = 95 N/m and x = 0.65 m:

EE = ½ (95 N/m) (0.65 m)²

EE = 20. J

User Soheil Pourbafrani
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