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using slope intercept form, what is the equation of a line that passes through the origin and point (5, 12)?

User Sabacc
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Answer:

Explanation:

y - y₁ = m(x - x₁)

where (x₁, y₁) is the given point (5,12), and m is the slope.

Since the line passes through the origin (0,0), the point (0,0) is on the line as well. Now, plug in the values:

y - 0 = m(x - 0)

Simplifying further:

y = mx

Now, to find the value of the slope (m), use the given point (5,12):

12 = m(5)

Now, solve for m:

m = 12/5

So, the slope (m) is 12/5. Now, you can write the equation in slope-intercept form using the slope and the y-intercept (which is 0 since the line passes through the origin):

y = (12/5)x

Therefore, the equation of the line that passes through the origin and the point (5,12) in slope-intercept form is:

y = (12/5)x

User Przemek
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