150k views
4 votes
Find the area of the region inside r = 10sin theta and outside r = 3 , round your answer to four digits after the decimal. QUESTION 5 Find the arc length of the polar curve described by r = 5 + 5cos theta

1 Answer

4 votes

The area of the region is approximately 47.1239 square units and the arc length of the polar curve is 25π units.

Area of the Region Inside r = 10sinθ and Outside r = 3

Set the equations equal to find where they intersect: 10sinθ = 3

Solve for θ: θ = arcsin(3/10) ≈ 0.3044 radians and θ = π - 0.3044 ≈ 2.8379 radians

The region lies between θ = 0.3044 and θ = 2.8379.

Area = 1/2 ∫[0.3044, 2.8379] [(10sinθ)^2 - 3^2] dθ

Area ≈ 47.1239 square units (rounded to four decimal places)

Arc Length of the Polar Curve r = 5 + 5cosθ

Formula for Arc Length in Polar Coordinates:

L = ∫[a, b] √[r^2 + (dr/dθ)^2] dθ

dr/dθ = -5sinθ

L = ∫[0, 2π] √[(5 + 5cosθ)^2 + (-5sinθ)^2] dθ

L ≈ 25π units (exact value)

User Wodesuck
by
7.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories