Answer:
Step-by-step explanation:
The question asks for the effect of an external magnetic field on a flat circular coil with specific characteristics. To determine this, we can use the formula for the magnetic flux through a coil, which is given by:
Φ = NAB
Where:
- Φ is the magnetic flux (measured in Weber)
- N is the number of turns in the coil
- A is the area of the coil
- B is the magnetic field strength
In this case, the coil has 199 turns and a radius of 2.01 x 10^(-6) m. To find the area, we can use the formula for the area of a circle:
A = πr^2
Substituting the values, we get:
A = π(2.01 x 10^(-6))^2
Now, the coil has a resistance of 0.679 Ω, which means that when a current flows through it, there will be a voltage drop across the coil. This voltage can be calculated using Ohm's law:
V = IR
Where:
- V is the voltage (measured in volts)
- I is the current (measured in amperes)
- R is the resistance (measured in ohms)
We can rearrange the formula to solve for the current:
I = V/R
Substituting the resistance value, we get:
I = V/0.679
Now, let's consider the effect of the external magnetic field. Since the field is directed perpendicular to the plane of the coil, the magnetic flux through the coil will be maximized. This means that the magnetic field lines will cut across the coil, inducing an electromotive force (EMF) and a current in the coil.
The induced EMF can be calculated using Faraday's law of electromagnetic induction:
EMF = -N(dΦ/dt)
Where:
- EMF is the electromotive force (measured in volts)
- N is the number of turns in the coil
- dΦ/dt is the rate of change of magnetic flux with respect to time
In this case, since the magnetic field strength is constant, the rate of change of magnetic flux is zero. Therefore, the induced EMF will be zero as well.
In summary, when the flat circular coil with 199 turns, a radius of 2.01 x 10^(-6) m, and a resistance of 0.679 Ω is exposed to an external magnetic field directed perpendicular to the plane of the coil, no induced EMF or current will be generated in the coil.