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Find two points on the graph of the parabola other than the vertex and x-intercepts. k(x)=(x−4)^2−4

User Newtt
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1 Answer

3 votes

Answer:

(0,12) and (1,5).

Explanation:

y = (x−4)^2 − 4.

The y-intercept occurs when x = 0 so

(0-4)^2 - 4

= 12

So one point is (0,12).

When x = 1,

y = (1-4)^2 - 4

= (-3)^2 - 4

= 5

So another point is (1, 5).

User Trevan
by
8.1k points

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