Final answer:
Ms. Jones has been administered a total of 2.625 grams of acetaminophen. With a maximum daily dose of 4 grams, she can have 4 more tablets of oxycodone/acetaminophen before exceeding the limit.
Step-by-step explanation:
To determine how many grams of acetaminophen has been administered to Ms. Jones, we need to calculate the total dosage she has taken over the specified period:
At 2100 hours, 2 tablets of 500 mg each: 2 x 500 mg = 1000 mg or 1 g
At 0100 hours, 2 tablets of oxycodone/acetaminophen 5/325 mg each: 2 x 325 mg = 650 mg or 0.65 g
At 0700 hours, 2 tablets of oxycodone/acetaminophen 5/325 mg each: 2 x 325 mg = 650 mg or 0.65 g
At 1100 hours, 1 tablet of oxycodone/acetaminophen 5/325 mg: 1 x 325 mg = 325 mg or 0.325 g
Adding these amounts together: 1 g + 0.65 g + 0.65 g + 0.325 g = 2.625 g.
Thus, a total of 2.625 grams of acetaminophen has been administered so far.
The maximum daily dose of acetaminophen is 4 g. Since 2.625 g has been given, the remaining amount that can be safely administered is 4 g - 2.625 g = 1.375 g. Since one tablet of oxycodone/acetaminophen contains 325 mg, to determine the maximum number of additional tablets:
1.375 g = 1375 mg
1375 mg / 325 mg per tablet ≈ 4.23 tablets.
Rounded to the nearest whole tablet, Ms. Jones can have 4 more tablets of oxycodone/acetaminophen before reaching the maximum daily dose.